Using CP = (Distance x Home) / (Out reduced + Home), if the total distance is 900 NM, Out 350 KTS, Home 250 KTS, the CP is approximately which value?

• A. 320 NM
• B. 480 NM
• C. 600 NM
• D. 375 NM

Answer: (D)

This tests applying the CP formula by balancing outbound and return speeds to locate a point along the route. Use CP = (Distance × Home) / (Out reduced + Home).

Plug in the numbers: Distance is 900 NM, Home speed is 250 KTS, Out reduced is 350 KTS. Denominator: 350 + 250 = 600. Numerator: 900 × 250 = 225,000. So CP = 225,000 / 600 = 375 NM.

So the CP is about 375 nautical miles from the start. The result makes intuitive sense: since outbound is faster than inbound, the balance point lies closer to the starting point than the halfway mark (450 NM).